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Question Number 167485 by Gbenga last updated on 17/Mar/22
∫∫∫xndx
Answered by puissant last updated on 18/Mar/22
∫∫∫xndx=∫∫{xn+1n+1+C}dx=∫{xn+2(n+1)(n+2)+Cx+d}dx=xn+3(n+1)(n+2)(n+3)+Cx2+dx+e.
Commented by Gbenga last updated on 18/Mar/22
ThanksSir
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