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Question Number 167716 by cortano1 last updated on 23/Mar/22
Answered by mahdipoor last updated on 23/Mar/22
⇒f′(x)=cosx+f′(x)(2sinx−sin2x)⇒f′(x)=cosx1+sin2x−2sinx=cosx(1−sinx)2⇒f(x)=∫cosx.dx(1−sinx)2=−∫(1−sinx)′(1−sinx)2=1(1−sinx)+C
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