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Question Number 167808 by Tawa11 last updated on 25/Mar/22

Commented by Tawa11 last updated on 25/Mar/22

Will the masses accelerate at 3.26m/s^2 .

$$\mathrm{Will}\:\mathrm{the}\:\mathrm{masses}\:\mathrm{accelerate}\:\mathrm{at}\:\:\:\mathrm{3}.\mathrm{26m}/\mathrm{s}^{\mathrm{2}} . \\ $$

Answered by qaz last updated on 25/Mar/22

(M+m)a=Mg−μmg ⇒a=((Mg−μmg)/(M+m))=4.9m/s^2 I′m not sure if it′s right.

$$\left(\mathrm{M}+\mathrm{m}\right)\mathrm{a}=\mathrm{Mg}−\mu\mathrm{mg} \\ $$$$\Rightarrow\mathrm{a}=\frac{\mathrm{Mg}−\mu\mathrm{mg}}{\mathrm{M}+\mathrm{m}}=\mathrm{4}.\mathrm{9m}/\mathrm{s}^{\mathrm{2}} \\ $$$$\mathrm{I}'\mathrm{m}\:\mathrm{not}\:\mathrm{sure}\:\mathrm{if}\:\mathrm{it}'\mathrm{s}\:\mathrm{right}. \\ $$

Commented by Tawa11 last updated on 25/Mar/22

This is what they got sir. Please show the motion on diagram sir. Thanks. God bless you.

$$\mathrm{This}\:\mathrm{is}\:\mathrm{what}\:\mathrm{they}\:\mathrm{got}\:\mathrm{sir}. \\ $$$$\mathrm{Please}\:\mathrm{show}\:\mathrm{the}\:\mathrm{motion}\:\mathrm{on}\:\mathrm{diagram}\:\mathrm{sir}.\:\mathrm{Thanks}. \\ $$$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}. \\ $$

Commented by Tawa11 last updated on 25/Mar/22

I understand now sir. Thanks.

$$\mathrm{I}\:\mathrm{understand}\:\mathrm{now}\:\mathrm{sir}.\:\mathrm{Thanks}. \\ $$

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