Question Number 168072 by pete last updated on 02/Apr/22
$$\mathrm{The}\:\mathrm{ratio}\:\mathrm{of}\:\mathrm{cars}\:\mathrm{to}\:\mathrm{motorcycles}\:\mathrm{sold}\:\mathrm{in}\:\mathrm{a} \\ $$$$\mathrm{garage}\:\mathrm{is}\:\mathrm{5}:\mathrm{7}.\:\mathrm{If}\:\mathrm{a}\:\mathrm{dealer}\:\mathrm{sold}\:\mathrm{142}\:\mathrm{more}\: \\ $$$$\mathrm{motorcycles}\:\mathrm{than}\:\mathrm{cars}\:\mathrm{in}\:\mathrm{a}\:\mathrm{particular}\:\mathrm{month}, \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{each}\:\mathrm{type}\:\mathrm{of}\:\mathrm{vehicle} \\ $$$$\mathrm{sold}. \\ $$
Answered by antrose last updated on 02/Apr/22
$$\mathrm{7}{x}−\mathrm{5}{x}=\mathrm{142} \\ $$$$\mathrm{2}{x}=\mathrm{142} \\ $$$${x}=\mathrm{71} \\ $$$${number}\:{of}\:{cars}=\mathrm{5}{x} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\mathrm{355} \\ $$$${number}\:{of}\:{motorcycles}=\mathrm{7}{x} \\ $$$$ \\ $$
Commented by pete last updated on 05/Apr/22
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{so}\:\mathrm{much} \\ $$
Answered by Rasheed.Sindhi last updated on 02/Apr/22
![c:m=5:7 [c:cars sold, m:motorcycles sold] (c/(c+142))=(5/7) [in a particular month] 7c=5c+710 c=355 m=c+142=355+142=497](Q168077.png)
$${c}:{m}=\mathrm{5}:\mathrm{7}\:\:\left[{c}:{cars}\:{sold},\:{m}:{motorcycles}\:{sold}\right] \\ $$$$\frac{{c}}{{c}+\mathrm{142}}=\frac{\mathrm{5}}{\mathrm{7}}\:\left[{in}\:{a}\:{particular}\:{month}\right] \\ $$$$\mathrm{7}{c}=\mathrm{5}{c}+\mathrm{710} \\ $$$${c}=\mathrm{355} \\ $$$${m}={c}+\mathrm{142}=\mathrm{355}+\mathrm{142}=\mathrm{497} \\ $$
Commented by pete last updated on 05/Apr/22
$$\mathrm{thank}\:\mathrm{you} \\ $$