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Question Number 168073 by pete last updated on 02/Apr/22

The unit digit of a two degit number is 1 less  than the tens degit. if the number is increased  by 8 and then divided by the sum of the  digits, the result is 8. Find the number.

$$\mathrm{The}\:\mathrm{unit}\:\mathrm{digit}\:\mathrm{of}\:\mathrm{a}\:\mathrm{two}\:\mathrm{degit}\:\mathrm{number}\:\mathrm{is}\:\mathrm{1}\:\mathrm{less} \\ $$$$\mathrm{than}\:\mathrm{the}\:\mathrm{tens}\:\mathrm{degit}.\:\mathrm{if}\:\mathrm{the}\:\mathrm{number}\:\mathrm{is}\:\mathrm{increased} \\ $$$$\mathrm{by}\:\mathrm{8}\:\mathrm{and}\:\mathrm{then}\:\mathrm{divided}\:\mathrm{by}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{digits},\:\mathrm{the}\:\mathrm{result}\:\mathrm{is}\:\mathrm{8}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{number}. \\ $$

Answered by som(math1967) last updated on 02/Apr/22

10′s digit x  unit digit=x−1  number=10x+x−1=11x−1  11x−1+8=8(2x−1)  7+8=5x  x=3  unit digit=3−1=2  number is 32 ans  (32+8)÷(3+2)=8

$$\mathrm{10}'{s}\:{digit}\:{x} \\ $$$${unit}\:{digit}={x}−\mathrm{1} \\ $$$${number}=\mathrm{10}{x}+{x}−\mathrm{1}=\mathrm{11}{x}−\mathrm{1} \\ $$$$\mathrm{11}{x}−\mathrm{1}+\mathrm{8}=\mathrm{8}\left(\mathrm{2}{x}−\mathrm{1}\right) \\ $$$$\mathrm{7}+\mathrm{8}=\mathrm{5}{x} \\ $$$${x}=\mathrm{3} \\ $$$${unit}\:{digit}=\mathrm{3}−\mathrm{1}=\mathrm{2} \\ $$$${number}\:{is}\:\mathrm{32}\:{ans} \\ $$$$\left(\mathrm{32}+\mathrm{8}\right)\boldsymbol{\div}\left(\mathrm{3}+\mathrm{2}\right)=\mathrm{8} \\ $$

Commented by som(math1967) last updated on 02/Apr/22

I think sum of digits means  sum of digits of original number

$${I}\:{think}\:{sum}\:{of}\:{digits}\:{means} \\ $$$${sum}\:{of}\:{digits}\:{of}\:{original}\:{number} \\ $$

Commented by peter frank last updated on 02/Apr/22

thank you

$$\mathrm{thank}\:\mathrm{you} \\ $$

Commented by pete last updated on 05/Apr/22

Thank you senior

$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{senior} \\ $$

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