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Question Number 168161 by daus last updated on 05/Apr/22

Commented by daus last updated on 05/Apr/22

$$helpshowmetheway.thanks$$

Answered by alephzero last updated on 05/Apr/22

$$x^2-2x\cos \theta +1=0$$$$\Rightarrow x=\frac{2\cos \theta \pm \sqrt{4{\cos }^2\theta -4}}{2}=$$$$=\frac{2\cos \theta \pm \sqrt{4({\cos }^2\theta -1)}}{2}=$$$$=\cos \theta \pm \sqrt{{\cos }^2\theta -1}=$$$$=\cos \theta \pm i\mid \sin \theta \mid$$

Commented by peter frank last updated on 05/Apr/22

$$\mathrm{good}$$

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