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Question Number 168203 by Tawa11 last updated on 05/Apr/22

Answered by kapoorshah last updated on 05/Apr/22

(x+2)(y+3)=0  (y+3)(z+1)=0  (z+1)(x+2)=0  x = −2   y = −3   z = −1

$$\left({x}+\mathrm{2}\right)\left({y}+\mathrm{3}\right)=\mathrm{0} \\ $$$$\left({y}+\mathrm{3}\right)\left({z}+\mathrm{1}\right)=\mathrm{0} \\ $$$$\left({z}+\mathrm{1}\right)\left({x}+\mathrm{2}\right)=\mathrm{0} \\ $$$${x}\:=\:−\mathrm{2}\:\:\:{y}\:=\:−\mathrm{3}\:\:\:{z}\:=\:−\mathrm{1} \\ $$$$ \\ $$

Commented by Tawa11 last updated on 06/Apr/22

God bless you sir.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

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