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Question Number 168210 by mathlove last updated on 06/Apr/22

Answered by mr W last updated on 06/Apr/22

$$y=x^3+ex$$$$x^3+ex-y=0$$$$x=\sqrt[3]{\sqrt{\frac{e^3}{27}+\frac{y^2}{4}}+\frac{y}{2}}-\sqrt[3]{\sqrt{\frac{e^3}{27}+\frac{y^2}{4}}-\frac{y}{2}}$$$$f^{-1}\left(x\right)=\sqrt[3]{\sqrt{\frac{e^3}{27}+\frac{x^2}{4}}+\frac{x}{2}}-\sqrt[3]{\sqrt{\frac{e^3}{27}+\frac{x^2}{4}}-\frac{x}{2}}$$

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