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Question Number 168267 by Florian last updated on 07/Apr/22
Solvethisintegral:∫x+1−1x+1+1
Answered by MJS_new last updated on 07/Apr/22
∫x+1−1x+1+1dx=[t=x+1→dx=2tdt]=2∫t(t−1)t+1dt=∫(2t−4+4t+1)dt==t2−4t+4ln(t+1)==x−4x+1+4ln(1+x+1)+C
Commented by Florian last updated on 07/Apr/22
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