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Question Number 168400 by leicianocosta last updated on 10/Apr/22

Commented by cortano1 last updated on 10/Apr/22
${ ((5(√7) πx+2πy = ((2π(√7))/7))),((x −2πy = 10π^2 )) :} x(5(√7) π+1)=((2π(√7))/7)+10π^2 x=((2π(√7)+70π^2 )/(35π(√7)+7)) ; [π=((22)/7)]$
${\begin{cases} 5 \sqrt{7} π x + 2 π y = \frac{2 π \sqrt{7}}{7} \\ x - 2 π y = 10 π^{2} \end{cases}$ $x (5 \sqrt{7} π + 1) = \frac{2 π \sqrt{7}}{7} + 10 π^{2}$ $x = \frac{2 π \sqrt{7} + 70 π^{2}}{35 π \sqrt{7} + 7}; [π = \frac{22}{7}]$
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