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Question Number 168464 by Altaf180 last updated on 11/Apr/22
limx→01−cos7xx2=?
Commented by safojontoshtemirov last updated on 11/Apr/22
lim2x→0(sin27x2)/x2=lim2x→0⋅494(sin7x27x2)2==492
Answered by malwan last updated on 14/Apr/22
limx→01−{1−(7x)22!+...}x2=492
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