All Questions Topic List
Integration Questions
Previous in All Question Next in All Question
Previous in Integration Next in Integration
Question Number 168473 by Mastermind last updated on 11/Apr/22
Integrate:∫(1x−1)12dxMastermind
Answered by MJS_new last updated on 11/Apr/22
∫1−xxdx=[t=1−xx→dx=−2x2tdt]=−2∫t2(t2+1)2dt=tt2+1−arctant==(1−x)x−arctan1−xx+C
Commented by Mastermind last updated on 12/Apr/22
Thanksman
Terms of Service
Privacy Policy
Contact: info@tinkutara.com