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Question Number 168477 by infinityaction last updated on 11/Apr/22

Commented by mr W last updated on 11/Apr/22

$$\pi /3>1$$$$\Rightarrow {\cos }^{-1}\left(\pi /3\right)isnotdefined!$$$$questioniswrong!$$

Commented by infinityaction last updated on 11/Apr/22

$$no$$$$useoflimitafterintegration$$

Commented by mr W last updated on 11/Apr/22

$$soyouthink{\int }_0^2\sqrt{1-x^2}dxexists?$$

Commented by infinityaction last updated on 11/Apr/22

$$no$$$$ggotitsir$$

Commented by safojontoshtemirov last updated on 12/Apr/22

$$\underset{0}{\stackrel{\frac{\pi }{3}}{\int }}sinx\cdot cosxdx=\underset{0}{\stackrel{\frac{\pi }{3}}{\int }}sinxd\left(sinx\right)=\underset{0}{\stackrel{\frac{\sqrt{3}}{2}}{\int }}tdt$$$$\frac{t^2}{2}\underset{0}{\stackrel{\frac{\sqrt{3}}{2}}{\mid }}=\frac{3}{8}.$$

Commented by mr W last updated on 12/Apr/22

$${\cos }^{-1}x=\arccos x\ne \frac{1}{\cos x}$$

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