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Question Number 168617 by Tawa11 last updated on 14/Apr/22

Commented by mr W last updated on 14/Apr/22

since the position of particle at t=0 is  not specified, you can′t determine its  position at t=3.5 s.  assume at t=0 it is at the mean  position, then at t=3.5 s its position  is x=0.1 sin (((3.5)/(22))×2π)=0.084 m

$${since}\:{the}\:{position}\:{of}\:{particle}\:{at}\:{t}=\mathrm{0}\:{is} \\ $$$${not}\:{specified},\:{you}\:{can}'{t}\:{determine}\:{its} \\ $$$${position}\:{at}\:{t}=\mathrm{3}.\mathrm{5}\:{s}. \\ $$$${assume}\:{at}\:{t}=\mathrm{0}\:{it}\:{is}\:{at}\:{the}\:{mean} \\ $$$${position},\:{then}\:{at}\:{t}=\mathrm{3}.\mathrm{5}\:{s}\:{its}\:{position} \\ $$$${is}\:{x}=\mathrm{0}.\mathrm{1}\:\mathrm{sin}\:\left(\frac{\mathrm{3}.\mathrm{5}}{\mathrm{22}}×\mathrm{2}\pi\right)=\mathrm{0}.\mathrm{084}\:{m} \\ $$

Commented by Tawa11 last updated on 14/Apr/22

God bless you sir.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

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