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Question Number 168642 by Shrinava last updated on 15/Apr/22

Let  △ABC  be a triangle with  ∠ABC=60°  and  ∠ACB=50°.  IABI=a^2 −2 , IBCI=a  in this  instance , prove that  IACI=(√3).

$$\mathrm{Let}\:\:\bigtriangleup\mathrm{ABC}\:\:\mathrm{be}\:\mathrm{a}\:\mathrm{triangle}\:\mathrm{with} \\ $$$$\angle\mathrm{ABC}=\mathrm{60}°\:\:\mathrm{and}\:\:\angle\mathrm{ACB}=\mathrm{50}°. \\ $$$$\mathrm{IABI}=\mathrm{a}^{\mathrm{2}} −\mathrm{2}\:,\:\mathrm{IBCI}=\mathrm{a}\:\:\mathrm{in}\:\mathrm{this} \\ $$$$\mathrm{instance}\:,\:\mathrm{prove}\:\mathrm{that}\:\:\mathrm{IACI}=\sqrt{\mathrm{3}}. \\ $$

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