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Question Number 168663 by DomaPeti last updated on 15/Apr/22
howtosolve?cos(30°)⋅sin(45°)−cos(30°+dx)⋅sin(45°+dx)dx=?dx→0
Commented by cortano1 last updated on 15/Apr/22
limdx→0146−cos(30°+dx).sin(45°+dx)dx=limdx→0sin(30°+dx)sin(45°+dx)−cos(30°+dx)cos(45°+dx)1=sin30°sin45°−cos30°cos45°=142−146=142(1−3)
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