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Question Number 168909 by LEKOUMA last updated on 21/Apr/22

Resolve   (1−x^2 y)dx+(x^2 y−x^3 )dy=0 ; μ=μ(x)

$${Resolve}\: \\ $$$$\left(\mathrm{1}−{x}^{\mathrm{2}} {y}\right){dx}+\left({x}^{\mathrm{2}} {y}−{x}^{\mathrm{3}} \right){dy}=\mathrm{0}\:;\:\mu=\mu\left({x}\right) \\ $$

Commented by mr W last updated on 22/Apr/22

μ stands nowhere in the equation.

$$\mu\:{stands}\:{nowhere}\:{in}\:{the}\:{equation}. \\ $$

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