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Question Number 169139 by Shrinava last updated on 24/Apr/22

Commented by Shrinava last updated on 26/Apr/22

Perfect dear sir thankyou

$$\mathrm{Perfect}\:\mathrm{dear}\:\mathrm{sir}\:\mathrm{thankyou} \\ $$

Commented by mr W last updated on 26/Apr/22

Commented by mr W last updated on 26/Apr/22

ΔBCD is ΔACE after a rotation  by 60°.  It can be proved that GF intersects  AE and BD at an angle 60°. (see  proof later)  all angles of ΔHIK are 60°.

$$\Delta{BCD}\:{is}\:\Delta{ACE}\:{after}\:{a}\:{rotation} \\ $$$${by}\:\mathrm{60}°. \\ $$$${It}\:{can}\:{be}\:{proved}\:{that}\:{GF}\:{intersects} \\ $$$${AE}\:{and}\:{BD}\:{at}\:{an}\:{angle}\:\mathrm{60}°.\:\left({see}\right. \\ $$$$\left.{proof}\:{later}\right) \\ $$$${all}\:{angles}\:{of}\:\Delta{HIK}\:{are}\:\mathrm{60}°. \\ $$

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