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Question Number 169281 by mnjuly1970 last updated on 28/Apr/22

Commented by cortano1 last updated on 28/Apr/22

$$\tan \beta =\frac{1}{5},\tan (\alpha +\beta )=\frac{1}{2}$$$$\Rightarrow \tan \alpha =\frac{3}{11}$$$$\therefore \tan (45°+\alpha ).\tan (45°-\beta )=$$$$\frac{1+\frac{3}{11}}{1-\frac{3}{11}}.\frac{1-\frac{1}{5}}{1+\frac{1}{5}}=\frac{14}{8}.\frac{2}{3}=\frac{7}{6}$$

Commented by mnjuly1970 last updated on 28/Apr/22

$$merceymrcartano$$

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