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Question Number 169439 by Giantyusuf last updated on 30/Apr/22

Answered by mr W last updated on 30/Apr/22

$$a^2{x}^2+a^2{y}^2+b^2{x}^2+b^2{y}^2=81\times 121...\left(i\right)$$$$a^2{x}^2+b^2{y}^2+2abxy={99}^2...\left(ii\right)$$$$\left(i\right)-\left(ii\right):$$$$a^2{y}^2+b^2{x}^2-2abxy=81\times 121-{99}^2=0$$$${(ay-bx)}^2=0$$$$\Rightarrow ay-bx=0$$

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