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Question Number 169538 by BRR last updated on 02/May/22

Commented by Tinku Tara last updated on 02/May/22

$$\mathrm{fare}\mathrm{increase}5x$$$$\mathrm{total}\mathrm{earning}=(400-10x)\times (50+5x)$$$$f\left(x\right)=20000+1500x-50x^2$$$$f{}^{\prime }\left(x\right)=1500-100x$$$$x=15$$$$maxfare=50+15\times 5=125$$

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