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Question Number 169553 by ali009 last updated on 02/May/22

$$solvetheD.E$$$$2dx-e^{y-x}dy=0$$

Answered by som(math1967) last updated on 03/May/22

$$2dx=e^{y-x}dy$$$$2dx=\frac{e^{y}dy}{e^x}$$$$2\int e^{x}dx=\int e^{y}dy$$$$2e^x=e^y+C$$

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