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Question Number 169849 by cherokeesay last updated on 10/May/22

Answered by som(math1967) last updated on 11/May/22

Commented by som(math1967) last updated on 11/May/22

$$AO=\sqrt{2^2+1^2}=\sqrt{5}cm$$$$AL=\sqrt{5}-1$$$$EL=CE=hcm$$$$BE=2-h$$$${AE}^2=2^2+{(2-h)}^2$$$${AL}^2+h^2=4+4+h^2-4h$$$${(\sqrt{5}-1)}^2+h^2=8-4h+h^2$$$$6-2\sqrt{5}=8-4h$$$$h=\frac{2+2\sqrt{5}}{4}=\frac{\sqrt{5}+1}{2}$$$$areaof△AEO=\frac{1}{2}\times \sqrt{5}\times \frac{\sqrt{5}+1}{2}$$$$=\frac{5+\sqrt{5}}{4}{cm}^2$$$$$$

Commented by cherokeesay last updated on 11/May/22

$$greet!$$$$thankyousir!$$

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