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Question Number 169852 by Shrinava last updated on 10/May/22

$$\mathrm{y}={\mathrm{x}}^2+2$$$$\mathrm{y}=-\mathrm{x}$$$$\mathrm{x}=0$$$$\mathrm{x}=1$$$$\mathrm{find}\mathrm{the}\mathrm{area}\mathrm{of}\mathrm{the}\mathrm{figure}\mathrm{bounded}\mathrm{by}$$$$\mathrm{lines}$$

Answered by mahdipoor last updated on 11/May/22

$${\int }_0^1(x^2+2-(-x))dx={[\frac{x^3}{3}+2x+\frac{x^2}{2}]}_0^1=\frac{17}{6}$$

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