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Question Number 169892 by weltr last updated on 11/May/22

$$\frac{dy}{dx}=2{xe}^{-y},y\left(1\right)=0$$

Answered by mahdipoor last updated on 11/May/22

$$\Rightarrow \frac{dy}{e^{-y}}=e^{y}dy=2xdx\Rightarrow e^y=x^2+c$$$$\Rightarrow x=1,y=0\Rightarrow c=0$$$$\Rightarrow \Rightarrow e^y=x^2$$

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