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Question Number 169896 by Beginner last updated on 11/May/22

Answered by mr W last updated on 12/May/22

x−3≥0 ∧ 2x(x+1)>0 ⇒x≥3 ∧ x<−1 or x>0 ⇒x≥3 ✓ x−3≤0 ∧ 2x(x+1)<0 ⇒x≤3 ∧ −1<x<0 ⇒−1<x<0 ✓

x−3⩾0∧2x(x+1)>0⇒x⩾3∧x<−1orx>0⇒x⩾3✓x−3⩽0∧2x(x+1)<0⇒x⩽3∧−1<x<0⇒−1<x<0✓

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