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Question Number 169900 by pticantor last updated on 12/May/22

$$\mathit{m}\mathit{o}\mathit{n}\mathit{t}\mathit{r}\mathit{e}\mathit{r}\mathit{q}\mathit{u}\mathit{e}\mathrm{\forall }\mathit{z}\in \mathbb{C}/\mid \mathit{z}\mid =2,$$$$\mid \frac{1}{{\mathit{z}}^4-5\mathit{z}+1}\mid ⩽\frac{1}{5}$$

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