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Question Number 169987 by cortano1 last updated on 13/May/22

Answered by greougoury555 last updated on 13/May/22

PT_1  ≡ −32x+30y=254  PT_2  ≡ 3x−5y = 9   tan α = ((((16)/(15))−(3/5))/(1+((48)/(75)))) = ((35)/(123))

$${PT}_{\mathrm{1}} \:\equiv\:−\mathrm{32}{x}+\mathrm{30}{y}=\mathrm{254} \\ $$$${PT}_{\mathrm{2}} \:\equiv\:\mathrm{3}{x}−\mathrm{5}{y}\:=\:\mathrm{9} \\ $$$$\:\mathrm{tan}\:\alpha\:=\:\frac{\frac{\mathrm{16}}{\mathrm{15}}−\frac{\mathrm{3}}{\mathrm{5}}}{\mathrm{1}+\frac{\mathrm{48}}{\mathrm{75}}}\:=\:\frac{\mathrm{35}}{\mathrm{123}}\: \\ $$

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