[(16x^4 −1)]/[2x−1] factorise it


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Question Number 27213 by shiv15031973@gmail.com last updated on 04/Jan/18

$[(16 x^{4} - 1)] / [2 x - 1] f a c t o r i s e i t$
Commented by abdo imad last updated on 03/Jan/18

$16 x^{4} - 1 = {(4 x^{2})}^{2} - 1 = (4 x^{2} - 1) (4 x^{2} + 1)$ $(2 x - 1) (2 x + 1) (4 x^{2} + 1) t h i s i s t h e f a c t r s a t i o n i n s i n d R$ $b u t i n s i d e C$ $16 x^{4} - 1 = (2 x - 1) (2 x + 1) (2 x - i) (2 x + i) .$
	Answered by shiv15031973@gmail.com last updated on 04/Jan/18

	${(4 x^{2})}^{2} - {(1^{2})}^{2} = a^{2} - b^{2}$ $(4 x^{2} + 1) (4 x^{2} - 1)$ $[(4 x^{2} + 1) (2 x + 1) (2 \overset{\times}{x} - 1)] / (2 \overset{\times}{x} - 1)$ $∵ 8 x^{3} + 4 x^{2} + 2 x + 1$
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