Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 170084 by Beginner last updated on 16/May/22

Commented by cortano1 last updated on 16/May/22

   sin x=3((1/2) cos x+(1/2)(√3) sin x)     sin x= (3/2) cos x +(3/2)(√3) sin x   (((2−3(√3))/2))sin x = (3/2) cos x     tan x = (3/(2−3(√3))) = ((3(2+3(√3)))/(4−27))     tan x = −((6+9(√3))/(23))

sinx=3(12cosx+123sinx)sinx=32cosx+323sinx(2332)sinx=32cosxtanx=3233=3(2+33)427tanx=6+9323

Commented by mathlove last updated on 16/May/22

thanks

thanks

Terms of Service

Privacy Policy

Contact: info@tinkutara.com