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Question Number 170117 by mathlove last updated on 16/May/22

x^2 =4^x       x=?

x2=4xx=?

Commented by mathlove last updated on 16/May/22

x^2 =4^x   solve this befor Im fall

x2=4xsolvethisbeforImfall

Answered by mr W last updated on 16/May/22

x^2 =2^(2x)   x=±2^x   x=±e^(xln 2)   (−xln 2)e^(−xln 2) =±ln 2  −xln 2=W(±ln 2)  for x∈R:  ⇒x=−((W(ln 2))/(ln 2))≈−((0.44443609)/(ln 2))=−0.641186

x2=22xx=±2xx=±exln2(xln2)exln2=±ln2xln2=W(±ln2)forxR:x=W(ln2)ln20.44443609ln2=0.641186

Commented by mathlove last updated on 17/May/22

thanks

thanks

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