Question and Answers Forum

All Questions      Topic List

Coordinate Geometry Questions

Previous in All Question      Next in All Question      

Previous in Coordinate Geometry      Next in Coordinate Geometry      

Question Number 170181 by cortano1 last updated on 17/May/22

Answered by som(math1967) last updated on 18/May/22

$$\frac{1}{2}\times AB\times 4.5=\frac{1}{2}\times BC\times 5.5$$$$AB:BC=11:9$$$$letAB=11k,BC=9k$$$$\therefore BD=\frac{BC}{2}=4.5k$$$$\therefore {\left(11k\right)}^2={(4.5k)}^2+{(5.5)}^2$$$$121k^2-20.25k^2=30.25$$$$\Rightarrow k=\sqrt{\frac{30.25}{100.75}}=\frac{5.5}{\sqrt{100.75}}$$$$AB=11\times \frac{5.5}{\sqrt{100.75}}$$$$BD=4.5\times \frac{5.5}{\sqrt{100.75}}$$$$$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com