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Question Number 170182 by mathlove last updated on 18/May/22

lim_(x→0)  [x∙sin(1/x)]=?

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\left[{x}\centerdot{sin}\frac{\mathrm{1}}{{x}}\right]=? \\ $$

Commented by mr W last updated on 18/May/22

has [  ] special meaning? or you just mean  lim_(x→0)  (x∙sin(1/x))=?

$${has}\:\left[\:\:\right]\:{special}\:{meaning}?\:{or}\:{you}\:{just}\:{mean} \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\left({x}\centerdot{sin}\frac{\mathrm{1}}{{x}}\right)=? \\ $$

Answered by mr W last updated on 18/May/22

−∣x∣≤x sin (1/x)≤∣x∣  lim_(x→0) (−∣x∣)≤lim_(x→0) (x sin (1/x))≤lim_(x→0) ∣x∣  0≤lim_(x→0) (x sin (1/x))≤0  ⇒lim_(x→0) (x sin (1/x))=0

$$−\mid{x}\mid\leqslant{x}\:\mathrm{sin}\:\frac{\mathrm{1}}{{x}}\leqslant\mid{x}\mid \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(−\mid{x}\mid\right)\leqslant\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left({x}\:\mathrm{sin}\:\frac{\mathrm{1}}{{x}}\right)\leqslant\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\mid{x}\mid \\ $$$$\mathrm{0}\leqslant\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left({x}\:\mathrm{sin}\:\frac{\mathrm{1}}{{x}}\right)\leqslant\mathrm{0} \\ $$$$\Rightarrow\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left({x}\:\mathrm{sin}\:\frac{\mathrm{1}}{{x}}\right)=\mathrm{0} \\ $$

Commented by mathlove last updated on 18/May/22

thanks

$${thanks} \\ $$

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