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Question Number 170226 by ali009 last updated on 18/May/22
solve{x+y+z+w=0x+y+z+2w=02x+2y+3z+4w=12x+3y+4z+5w=2
Answered by floor(10²Eta[1]) last updated on 18/May/22
⇒x+y+z+w=x+y+z+2w⇒w=2w⇒w=0⇒{x+y+z=0(1)2x+2y+3z=1(2)2x+3y+4z=2(3)−2(1)+(2)⇒z=1(3):2x+3y=−2(2):2x+2y=−2⇒2x+3y=2x+2y⇒y=0∴x+y+z=0⇒x+0+1=0⇒x=−1
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