Question Number 170327 by mathlove last updated on 21/May/22
Answered by greougoury555 last updated on 21/May/22
$$\frac{\mathrm{1}}{\mathrm{log}\:_{{a}} \left({abc}\right)}\:+\:\frac{\mathrm{1}}{\mathrm{log}\:_{{b}} \left({abc}\right)}\:+\frac{\mathrm{1}}{\mathrm{log}\:_{{c}} \left({abc}\right)}\:=\: \\ $$$$\mathrm{log}\:_{{abc}} {a}+\mathrm{log}_{{abc}} {b}+\mathrm{log}\:_{{abc}} {c}\:=\:\mathrm{1}\: \\ $$