find tbe domain and range of the following functions y=4x/x^2 −4


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Question Number 170461 by khadee last updated on 24/May/22

$f i n d t b e d o m a i n a n d r a n g e o f t h e f o l l o w i n g f u n c t i o n s$ $y = 4 x / x^{2} - 4$
Commented by mokys last updated on 24/May/22
$x^2 −4=0⇒x=±2 Df= R−{±2}$
$x^{2} - 4 = 0 \Rightarrow x = \pm 2$ $D f = R - {\pm 2}$
	Answered by MathsFan last updated on 24/May/22
	$x^2 −4=0 x^2 =4 x=±2 domain={x∣x∈R,except x=±2}$
	$x^{2} - 4 = 0$ $x^{2} = 4$ $x = \pm 2$ $d o m a i n = {x ∣ x \in R, e x c e p t x = \pm 2}$
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