please help me to find this. a= ∫∫_D ((ydxdy)/(a^2 +x^2 )) D:{x≥0.y≥0.x^2 +y^2 ≤a^2 } b=∫∫∫_v (x−y+z)^2 dxdydz v:{x=0.y=0.z=0 x+z=1.y+z=1} c=∫∫∫


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Question Number 170545 by kndramaths last updated on 26/May/22
$please help me to find this. a= ∫∫_D ((ydxdy)/(a^2 +x^2 )) D:{x≥0.y≥0.x^2 +y^2 ≤a^2 } b=∫∫∫_v (x−y+z)^2 dxdydz v:{x=0.y=0.z=0 x+z=1.y+z=1} c=∫∫∫_V xydxdydz V:{0≤z≤1. x^2 +y^2 ≤z^2 }$
$p l e a s e h e l p m e t o f i n d t h i s .$ $a = \int \int_{D} \frac{y d x d y}{a^{2} + x^{2}} D : {x ⩾ 0 . y ⩾ 0 . x^{2} + y^{2} ⩽ a^{2}}$ $b = \int \int \int_{v} {(x - y + z)}^{2} d x d y d z$ $v : {x = 0 . y = 0 . z = 0 x + z = 1 . y + z = 1}$ $c = \int \int \int_{V} x y d x d y d z$ $V : {0 ⩽ z ⩽ 1 . x^{2} + y^{2} ⩽ z^{2}}$
Commented by kndramaths last updated on 27/May/22
$please help me to find this. a= ∫∫_D ((ydxdy)/(a^2 +x^2 )) D:{x≥0.y≥0.x^2 +y^2 ≤a^2 } b=∫∫∫_v (x−y+z)^2 dxdydz v:{x=0.y=0.z=0 x+z=1.y+z=1} c=∫∫∫_V xydxdydz V:{0≤z≤1. x^2 +y^2 ≤z^2 }$
$p l e a s e h e l p m e t o f i n d t h i s .$ $a = \int \int_{D} \frac{y d x d y}{a^{2} + x^{2}} D : {x ⩾ 0 . y ⩾ 0 . x^{2} + y^{2} ⩽ a^{2}}$ $b = \int \int \int_{v} {(x - y + z)}^{2} d x d y d z$ $v : {x = 0 . y = 0 . z = 0 x + z = 1 . y + z = 1}$ $c = \int \int \int_{V} x y d x d y d z$ $V : {0 ⩽ z ⩽ 1 . x^{2} + y^{2} ⩽ z^{2}}$
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