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Question Number 170565 by cortano1 last updated on 27/May/22

Answered by Mathspace last updated on 27/May/22

$$f^{{}^{\prime }}\left(x\right)=x^3\frac{2{(x+2)}^2}{1-3{(x+2)}^4}-x^3\frac{2{(x+1)}^2}{1-3{(x+1)}^4}$$$$\Rightarrow {lim}_{x\to +\mathrm{\infty }}{x}^3{f}^{{}^{\prime }}\left(x\right)=$$$${lim}_{x\to +\mathrm{\infty }}\frac{2x^5}{-3x^4}-\frac{2x^5}{-3x^4}=0$$$$$$

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