Question Number 170706 by help12345 last updated on 29/May/22
$$ \\ $$ Between 10:PM and 7:45AM the water level in a swimming pool decreased by 13÷16 (13/16)inch. Assuming that the water level decreased at a constant rate, how much did it drop each hour? The water level decreased by inch each hour.\\n
Commented byRasheed.Sindhi last updated on 29/May/22
$$\frac{\mathrm{1}}{\mathrm{12}}\:{inch}/{hour} \\ $$
Commented byhelp12345 last updated on 29/May/22
$${brother}\:{i}\:{need}\:{the}\:{solution}\:{step}\:{by}\:{step}\:{please} \\ $$
Answered by Rasheed.Sindhi last updated on 29/May/22
$$\mathcal{T}{otal}\:{period}\:{between}\:\mathrm{10}\:{pm}\:{and} \\ $$ $$\:\mathrm{7}:\mathrm{45}\:{am}:\:\mathrm{9}\:{hours}\:\mathrm{45}\:{minutes} \\ $$ $$=\mathrm{9}\frac{\mathrm{3}}{\mathrm{4}}=\frac{\mathrm{39}}{\mathrm{4}}\:{hours} \\ $$ $${Decrease}\:{during}\:{the}\:{period} \\ $$ $$=\mathrm{13}/\mathrm{16}\:{inch} \\ $$ $${Decrease}\:{per}\:{hour}=\frac{\mathrm{13}/\mathrm{16}}{\mathrm{39}/\mathrm{4}} \\ $$ $$\frac{\mathrm{13}}{\mathrm{16}}×\frac{\mathrm{4}}{\mathrm{39}}=\frac{\mathrm{\color{mathred}{1}}}{\mathrm{\color{mathred}{1}\color{mathred}{2}}}\color{mathred}{\:}{\color{mathred}{i}\color{mathred}{n}\color{mathred}{c}\color{mathred}{h}} \\ $$