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Question Number 170706 by help12345 last updated on 29/May/22

Between 10:PM and 7:45AM the water level in a swimming pool decreased by 13÷16 (13/16)inch. Assuming that the water level decreased at a constant rate, how much did it drop each hour? The water level decreased by inch each hour.\n
Commented byRasheed.Sindhi last updated on 29/May/22

$\frac{1}{12} i n c h / h o u r$
Commented byhelp12345 last updated on 29/May/22

$b r o t h e r i n e e d t h e s o l u t i o n s t e p b y s t e p p l e a s e$
	Answered by Rasheed.Sindhi last updated on 29/May/22

	$T o t a l p e r i o d b e t w e e n 10 p m a n d$ $7 : 45 a m : 9 h o u r s 45 m i n u t e s$ $= 9 \frac{3}{4} = \frac{39}{4} h o u r s$ $D e c r e a s e d u r i n g t h e p e r i o d$ $= 13 / 16 i n c h$ $D e c r e a s e p e r h o u r = \frac{13 / 16}{39 / 4}$ $\frac{13}{16} \times \frac{4}{39} = \frac{1}{12} i n c h$
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