Question and Answers Forum

All Questions      Topic List

Trigonometry Questions

Previous in All Question      Next in All Question      

Previous in Trigonometry      Next in Trigonometry      

Question Number 170752 by balirampatel last updated on 30/May/22

$$Solve:-\frac{sin\mathit{x}+cos\mathit{x}}{sin\mathit{x}-cos\mathit{x}}=\frac{\sqrt{3}-1}{\sqrt{3}+1}$$

Answered by Rasheed.Sindhi last updated on 30/May/22

$$\frac{sin\mathit{x}+cos\mathit{x}}{sin\mathit{x}-cos\mathit{x}}=\frac{\sqrt{3}-1}{\sqrt{3}+1}$$$$\overline{)\begin{array}{c}\frac{a}{b}=\frac{c}{d}\Rightarrow \frac{a+b}{a-b}=\frac{c+d}{c-d}\end{array}}$$$$\frac{(sin\mathit{x}+cos\mathit{x})+(sin\mathit{x}-cos\mathit{x})}{(sin\mathit{x}+cos\mathit{x})-(sin\mathit{x}-cos\mathit{x})}$$$$=\frac{(\sqrt{3}-1)+(\sqrt{3}+1)}{(\sqrt{3}-1)-(\sqrt{3}+1)}$$$$\frac{2sinx}{2cosx}=\frac{2\sqrt{3}}{-2}$$$$tanx=-\sqrt{3}$$$$x=-\frac{\pi }{3}+n\pi$$

Answered by Rasheed.Sindhi last updated on 30/May/22

$$\frac{sin\mathit{x}+cos\mathit{x}}{sin\mathit{x}-cos\mathit{x}}=\frac{\sqrt{3}+(-1)}{\sqrt{3}-(-1)}$$$$\overline{)\begin{array}{c}\frac{a+b}{a-b}=\frac{c+d}{c-d}\Rightarrow \frac{a}{b}=\frac{c}{d}\end{array}}$$$$\frac{sinx}{cosx}=\frac{\sqrt{3}}{-1}$$$$tanx=-\sqrt{3}$$$$x=-\frac{\pi }{3}+n\pi$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com