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Question Number 170906 by MASANJAJJ last updated on 03/Jun/22

Answered by thfchristopher last updated on 03/Jun/22

$$\frac{2}{5}=\frac{2600}{S}$$$$S=6500\mathrm{litres}\left(\mathrm{The}\mathrm{second}\mathrm{tank}\mathrm{volume}\right)$$$$\mathrm{Total}\mathrm{volumes}\mathrm{of}\mathrm{two}\mathrm{tanks}$$$$=2600+6500$$$$=9100\mathrm{litres}$$

Answered by Rasheed.Sindhi last updated on 04/Jun/22

$$2parts=2600liters$$$$1...=1300liters$$$$\mathcal{T}hetotalvolume=2+5=7parts$$$$=1300\times 7=9100liters$$

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