Question Number 170906 by MASANJAJJ last updated on 03/Jun/22
Answered by thfchristopher last updated on 03/Jun/22
$$\frac{\mathrm{2}}{\mathrm{5}}=\frac{\mathrm{2600}}{{S}} \\ $$$${S}=\mathrm{6500}\:\mathrm{litres}\:\left(\mathrm{The}\:\mathrm{second}\:\mathrm{tank}\:\mathrm{volume}\right) \\ $$$$\mathrm{Total}\:\mathrm{volumes}\:\mathrm{of}\:\mathrm{two}\:\mathrm{tanks} \\ $$$$=\mathrm{2600}+\mathrm{6500} \\ $$$$=\mathrm{9100}\:\mathrm{litres} \\ $$
Answered by Rasheed.Sindhi last updated on 04/Jun/22
$$\:\mathrm{2}\:{parts}=\mathrm{2600}\:{liters} \\ $$$$\:\:\mathrm{1}\:\:\:\:...\:\:\:\:=\mathrm{1300}\:{liters} \\ $$$$\mathcal{T}{he}\:{total}\:{volume}=\mathrm{2}+\mathrm{5}=\mathrm{7}\:{parts} \\ $$$$=\mathrm{1300}×\mathrm{7}=\mathrm{9100}\:{liters} \\ $$