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Question Number 170911 by MathsFan last updated on 03/Jun/22

A manufacturing company produces  containers(jugs) of the same kind. Two  similar containers of height 1.5cm  and 8cm were selected and filled with  orange juice for some athletes. Determine   the quantity of orange juice in the  smaller container if the bigger one   contained 7liters.

$$\boldsymbol{\mathrm{A}}\:\boldsymbol{\mathrm{manufacturing}}\:\boldsymbol{\mathrm{company}}\:\boldsymbol{\mathrm{produces}} \\ $$$$\boldsymbol{\mathrm{containers}}\left(\boldsymbol{\mathrm{jugs}}\right)\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{same}}\:\boldsymbol{\mathrm{kind}}.\:\boldsymbol{\mathrm{Two}} \\ $$$$\boldsymbol{\mathrm{similar}}\:\boldsymbol{\mathrm{containers}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{height}}\:\mathrm{1}.\mathrm{5}\boldsymbol{\mathrm{cm}} \\ $$$$\boldsymbol{\mathrm{and}}\:\mathrm{8}\boldsymbol{\mathrm{cm}}\:\boldsymbol{\mathrm{were}}\:\boldsymbol{\mathrm{selected}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{filled}}\:\boldsymbol{\mathrm{with}} \\ $$$$\boldsymbol{\mathrm{orange}}\:\boldsymbol{\mathrm{juice}}\:\boldsymbol{\mathrm{for}}\:\boldsymbol{\mathrm{some}}\:\boldsymbol{\mathrm{athletes}}.\:\boldsymbol{\mathrm{Determine}} \\ $$$$\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{quantity}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{orange}}\:\boldsymbol{\mathrm{juice}}\:\boldsymbol{\mathrm{in}}\:\boldsymbol{\mathrm{the}} \\ $$$$\boldsymbol{\mathrm{smaller}}\:\boldsymbol{\mathrm{container}}\:\boldsymbol{\mathrm{if}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{bigger}}\:\boldsymbol{\mathrm{one}} \\ $$$$\:\boldsymbol{\mathrm{contained}}\:\mathrm{7}\boldsymbol{\mathrm{liters}}. \\ $$

Answered by Rasheed.Sindhi last updated on 04/Jun/22

Jug of height 1.5 cm :)    x liters in smaller jug  x:7=1.5:8  8x=7×1.5  x=((10.5)/8)=1.3125 liters.

$$\left.\mathrm{Jug}\:\mathrm{of}\:\mathrm{height}\:\mathrm{1}.\mathrm{5}\:\mathrm{cm}\::\right) \\ $$$$ \\ $$$${x}\:{liters}\:{in}\:{smaller}\:{jug} \\ $$$${x}:\mathrm{7}=\mathrm{1}.\mathrm{5}:\mathrm{8} \\ $$$$\mathrm{8}{x}=\mathrm{7}×\mathrm{1}.\mathrm{5} \\ $$$${x}=\frac{\mathrm{10}.\mathrm{5}}{\mathrm{8}}=\mathrm{1}.\mathrm{3125}\:{liters}. \\ $$

Commented by MathsFan last updated on 04/Jun/22

thanks a lot

$${thanks}\:{a}\:{lot} \\ $$

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