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Question Number 170980 by anas_zaidan last updated on 05/Jun/22

Answered by aleks041103 last updated on 05/Jun/22

∫_2 ^4 ∫_0 ^1 x^2 ydxdy=  =(∫_0 ^1 x^2 dx)(∫_2 ^4 ydy)=  =((1/3)−(0/3))(((4^2 −2^2 )/2))=  =(1/6)(16−4)=2

4210x2ydxdy==(10x2dx)(42ydy)==(1303)(42222)==16(164)=2

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