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Question Number 170986 by Tawa11 last updated on 05/Jun/22

Commented by mr W last updated on 05/Jun/22

$$tooeasy...$$$$Acovers\frac{15}{15+10}=\frac{3}{5}$$$$Bcovers\frac{10}{15+10}=\frac{2}{5}$$

Commented by Tawa11 last updated on 06/Jun/22

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

Answered by thfchristopher last updated on 05/Jun/22

$$\mathrm{Let}t\mathrm{be}\mathrm{the}\mathrm{time}\mathrm{lapse}\mathrm{for}\mathrm{their}\mathrm{collision}$$$$\mathrm{Assume}\mathrm{they}\mathrm{each}\mathrm{travel}\mathrm{at}\mathrm{same}\mathrm{speed}\mathrm{without}\mathrm{acceleration}$$$$15t+10t=300\times 1000$$$$\Rightarrow 25t=300000$$$$\Rightarrow t=12000\sec$$$$\mathrm{i}.\mathrm{e}.\mathrm{Train}\mathrm{A}\mathrm{travels}15\times 12000=180\mathrm{km}$$$$=\frac{3}{5}\mathrm{of}\mathrm{total}\mathrm{distance}$$$$\Rightarrow \mathrm{Train}\mathrm{B}\mathrm{travels}120\mathrm{km}=\frac{2}{5}\mathrm{of}\mathrm{total}\mathrm{distance}$$$$$$

Commented by Tawa11 last updated on 06/Jun/22

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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