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Question Number 171014 by Beginner last updated on 06/Jun/22

Answered by greougoury555 last updated on 06/Jun/22

$$=\int (\frac{1}{7}{e}^{7x}+3e^{-2x})dx$$$$=\frac{1}{49}{e}^{7x}-\frac{3}{2}{e}^{-2x}+c$$

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