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Question Number 171032 by Mastermind last updated on 06/Jun/22

Find the domain and range of the  function, f(x)=((x^2 +2)/(2x+1))    Mastermind

Findthedomainandrangeofthefunction,f(x)=x2+22x+1Mastermind

Answered by cortano1 last updated on 06/Jun/22

 D_f = x≠−(1/2) ; x∈R   2xy+y=x^2 +2  ⇒x^2 −2xy+2−y=0  ⇒Δ = 4y^2 −4.1.(2−y)≥0  ⇒y^2 +y−2≥0  ⇒(y+2)(y−1)≥0  ⇒R_f  : y≤−2 ∨ y≥1

Df=x12;xR2xy+y=x2+2x22xy+2y=0Δ=4y24.1.(2y)0y2+y20(y+2)(y1)0Rf:y2y1

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