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Question Number 171091 by pablo1234523 last updated on 07/Jun/22

Commented by pablo1234523 last updated on 07/Jun/22

$$\mathrm{how}\mathrm{is}\mathrm{the}\mathrm{red}\mathrm{expression}\mathrm{obtained}$$$$f^{2n+1}\left(\theta x\right)=\cos (\frac{(2n+1)\pi }{2}+\theta x)=\cos (n\pi +\frac{\pi }{2}+\theta x)$$$$=-\sin (n\pi +\theta x)={(-1)}^n\sin \left(\theta x\right)$$$$$$$$\mathrm{but}\mathrm{the}\mathrm{book}\mathrm{is}\mathrm{showing}{f}^{2n+1}\left(\theta x\right)={(-1)}^{n+1}\cos \left(\theta x\right)$$

Commented by pablo1234523 last updated on 07/Jun/22

$$pleasehelp$$

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