Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 171136 by pablo1234523 last updated on 08/Jun/22

Using Taylor′s theorem, prove that  x−(x^3 /6)<sin x<x−(x^3 /6)+(x^5 /(120))   for x>0

$$\mathrm{Using}\:\mathrm{Taylor}'\mathrm{s}\:\mathrm{theorem},\:\mathrm{prove}\:\mathrm{that} \\ $$ $${x}−\frac{{x}^{\mathrm{3}} }{\mathrm{6}}<\mathrm{sin}\:{x}<{x}−\frac{{x}^{\mathrm{3}} }{\mathrm{6}}+\frac{{x}^{\mathrm{5}} }{\mathrm{120}}\:\:\:\mathrm{for}\:{x}>\mathrm{0} \\ $$

Commented bypablo1234523 last updated on 08/Jun/22

Commented bypablo1234523 last updated on 08/Jun/22

↑ example

$$\uparrow\:\mathrm{example} \\ $$

Commented bypablo1234523 last updated on 08/Jun/22

Commented bypablo1234523 last updated on 08/Jun/22

θx>0  what does it imply about cos (θx)?

$$\theta{x}>\mathrm{0} \\ $$ $$\mathrm{what}\:\mathrm{does}\:\mathrm{it}\:\mathrm{imply}\:\mathrm{about}\:\mathrm{cos}\:\left(\theta{x}\right)? \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com