Question Number 17129 by virus last updated on 01/Jul/17
Answered by ajfour last updated on 01/Jul/17
![v_(avg) =((∣△r∣)/(△t))=((2rsin (θ/2))/(rθ/v)) = v[((sin (θ/2))/((θ/2)))] , a_(avg) =((∣△v∣)/(△t))=((2vsin (θ/2))/(rθ/v)) = (v^2 /r)[((sin (θ/2))/((θ/2)))] .](Q17134.png)
$$\mathrm{v}_{\mathrm{avg}} =\frac{\mid\bigtriangleup\boldsymbol{\mathrm{r}}\mid}{\bigtriangleup\mathrm{t}}=\frac{\mathrm{2rsin}\:\left(\theta/\mathrm{2}\right)}{\mathrm{r}\theta/\mathrm{v}} \\ $$$$\:\:\:\:\:\:\:=\:\mathrm{v}\left[\frac{\mathrm{sin}\:\left(\theta/\mathrm{2}\right)}{\left(\theta/\mathrm{2}\right)}\right]\:, \\ $$$$\mathrm{a}_{\mathrm{avg}} =\frac{\mid\bigtriangleup\boldsymbol{\mathrm{v}}\mid}{\bigtriangleup\mathrm{t}}=\frac{\mathrm{2vsin}\:\left(\theta/\mathrm{2}\right)}{\mathrm{r}\theta/\mathrm{v}} \\ $$$$\:\:\:\:\:\:\:=\:\frac{\mathrm{v}^{\mathrm{2}} }{\mathrm{r}}\left[\frac{\mathrm{sin}\:\left(\theta/\mathrm{2}\right)}{\left(\theta/\mathrm{2}\right)}\right]\:. \\ $$
Commented by ajfour last updated on 01/Jul/17
Commented by virus last updated on 01/Jul/17
$${thank}\:{you}\:{sir} \\ $$