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Question Number 171296 by dragan91 last updated on 11/Jun/22

Commented by Rasheed.Sindhi last updated on 13/Jun/22

$$Forx>5{xy}^3+{xy}^3+2022<20x!+22y!$$$$Fory>5{xy}^3+{xy}^3+2022<20x!+22y!$$$$thismeans{we}^{\prime }vetosearchvalues$$$$between0\mathrm{\&}5forx,y.$$$$....$$$$x=5,y=3Ans$$

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